반응형
목록 백준 1935 (1)
KEEP GOING
[python] 백준 1935번 : 후위 표기식2
1. 코드 구현 n = int(input()) postfix = input() operator = ['*', '-', '+', '/'] stack = [] numbers = dict() for i in range(n): number = input() for data in postfix: if data == chr(i+65): numbers[data] = number for data in postfix: # data가 문자라면 ex A, B, C, D, ... if data not in operator: stack.append(data) else: w2 = stack.pop() w1 = stack.pop() if 'A'
code review/stack-queue
2022. 1. 27. 16:29
